Help dividing area measures lengthwise

[Madi Feil]

I am looking for some help trying to make a specific type of area measure.
The problem is this: I have an irregular shape that goes from left to right
lengthwise. What I would like to be able to do is divide the shape into 5
even pieces lengthwise, and then measure only the area of the shape that is
within each of the five segments. When doing this by drawing boxes around
segments, some of the area is lost due to the lines which restrict us from
selecting the full area within the section. I believe there should be a
simple way to do this, and would appreciate if anyone has guidance!

Thanks
- [hidden email]

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[sibert]

It isn't exactly clear to me what you are looking for or what the
difficulty is.  Perhaps something like this macro would be useful for you?

   orig = roiManager("index"); //gives index of current selection
   array = newArray(orig,roiManager("
count")-1); //initialize array variable
   getSelectionBounds(x,y,w,h); //returns rectangle containing original ROI
   width = w/5; //divide width into 5 even slices

   function myFunction(foo, bar) {

      makeRectangle(foo,y,width,h); //draw rectangle encompassing 1/5th
width of original
      roiManager("Add"); //add rectangle to ROI manager
      bar[1] += 1; //add index of new rectangle to array
      roiManager("select", bar); //select array
      roiManager("AND"); //find overlap of original and new rectangle
      roiManager("Add"); //add new ROI containing only overlap
      roiManager("deselect"); //deselect all ROIs
      roiManager("select", bar[1]); //select 1/5th rectangle
      roiManager("Delete"); //delete 1/5th rectangle
      return bar[1]
   }

   for (i=0; i<5; i++) {

      array[1] = myFunction(x+(i*width), array);

   }

   roiManager("deselect"); //deselect all ROIs
   roiManager("Measure"); //measure all ROIs (original and each 5th)


On Fri, Jun 7, 2013 at 3:56 PM, Madi Feil <[hidden email]> wrote:

> I am looking for some help trying to make a specific type of area measure.
> The problem is this: I have an irregular shape that goes from left to right
> lengthwise. What I would like to be able to do is divide the shape into 5
> even pieces lengthwise, and then measure only the area of the shape that is
> within each of the five segments. When doing this by drawing boxes around
> segments, some of the area is lost due to the lines which restrict us from
> selecting the full area within the section. I believe there should be a
> simple way to do this, and would appreciate if anyone has guidance!
>
> Thanks
> - [hidden email]
>
> --
> ImageJ mailing list: http://imagej.nih.gov/ij/list.html
>

... [show rest of quote]

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