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This does not work. Some of the cell are in the ROI and some of them
are outside.
I tried with the following test and I got values=0 or 255. This mean
the fit curve goes throught the boundary. looks bizarre...
labels = newArray(3);
labels[0] = "X";
labels[1] = "Y";
labels[2] = "values";
run("Fit Spline", "straighten");
getSelectionCoordinates(x, y);
for (i=1; i<x.length; i++) {
value =getPixel(x[i-1],y[i-1]);
setResult(labels[0], i, x[i-1]);
setResult(labels[1], i, y[i-1]);
setResult(labels[2], i, value);
}
updateResults();
****************************************
I need the list of ALL the coordinates and all the corresponding
grey values
of an ROI. (This ROI is a boundary).
- Save As \ Coordinate XY does not work for this because it gives
only the
extremities of boundaries segments (when they are vertical or
horizontal).
So, few data are missing.
- getSelectionCoordinates(x, y); does not work too for the same reason.
Is there a way to get ALL the coordinates of an ROI (boundaries or
area ROI) ?
Thank you
Eric
------------------------------------------------------------------------
You can often find answers to these questions by searching the ImageJ
archives. :-)
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On Sep 24, 2008, at 6:29 AM, Adam Cliffe wrote:
> Does anyone have a macro which will list all of the coordinates for an
> ROI?
> (not just the ends of the vertices)
One way to do this is to run the Edit>Selection>Fit Spline command with
the "straighten" option, which is what the Edit>Selection>Straighten
command does to get coordinates along a line spaced one pixel apart.
Here is an example:
requires("1.41i");
run("Fit Spline", "straighten");
getSelectionCoordinates(x, y);
for (i=1; i<x.length; i++) {
distance =
sqrt((x[i]-x[i-1])*(x[i]-x[i-1])+(y[i]-y[i-1])*(y[i]-y[i-1]));
print(i, x[i], y[i], distance);
}
-wayne
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