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Hi,
In the following class, I'm trying to convert a FloatProcessor with 4
differents values (one of them is Float.NaN) into a BufferedImage. The
resulting BufferedImage contains only 3 different colors : I mean, NaN pixel
value and smallest pixel value produce same pixel color. What's the way to
solve this problem (obtain 4 different pixel colors) ?
Thanks a lot,
The execution trace :
pixel value : 33.0
pixel value : 70.3
pixel value : NaN
pixel value : 244.4
Number of different colors = 3
color value : -16777216
color value : -1
color value : -13882324
public class ToBeDeleted {
private static BufferedImage toBufferedImage(Image image) {
if (image instanceof BufferedImage) {
return ((BufferedImage) image);
} else {
image = new ImageIcon(image).getImage();
final BufferedImage bufferedImage = new BufferedImage(image
.getWidth(null), image.getHeight(null),
BufferedImage.TYPE_INT_RGB);
final Graphics g = bufferedImage.createGraphics();
g.drawImage(image, 0, 0, null);
g.dispose();
return bufferedImage;
}
}
public static void main(String[] args) {
final float xxx = Float.NaN;
final ImageProcessor fp = new FloatProcessor(4, 1, new float[] { 33,
70.3f, xxx, 244.4f }, null);
// fp.resetMinAndMax();
// fp.autoThreshold();
final ImagePlus imagePlus = new ImagePlus("test", fp);
final BufferedImage bi = toBufferedImage(imagePlus.getImage());
for (float item : (float[]) fp.getPixels()) {
System.out.println("\tpixel value : " + item);
}
final Set<Integer> colorSet = new HashSet<Integer>();
for (int r = 0; r < bi.getWidth(); r++) {
for (int c = 0; c < bi.getHeight(); c++) {
colorSet.add(bi.getRGB(r, c));
}
}
System.out.println("Number of different colors = " + colorSet.size());
for (int item : colorSet) {
System.out.println("+++" + item);
}
// new ImagePlus("test", fp).show();
}
}
--
Thomas LEDUC
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