reset the ResultsTable counter?

[Aryeh Weiss]

I want to built a ResultsTable by adding a set of column to the
ResultsTable.

my code is:

for i in objectIndicesSet:
     tempAreaList =  [objectAreas[j] for j in range(len(objectAreas)) if
objectIndices[j] == i]
     print tempAreaList
     # here is where I wodl like to reset the Counter
     for k in tempAreaList:
         rtRearranged.incrementCounter()
         rtRearranged.addValue("Object "+str(i), k)

where I am adding the list tempAreaList to a column labeled "Object #"

This works, except that I cannot find a way to reset the Counter, so
when the second column is written (ie when "Object #" changes, and a new
column is automatically created), the counter is still on the last row
and the next column starts there. What I really want to do is have the
new column start at the first row again,     as I indicate with a
comment above.

Is this possible,  or do I have to create all of the area lists, and the
write tehm out one row at a time?

Thanks in advance.
--aryeh

--
Aryeh Weiss
Faculty of Engineering
Bar Ilan University
Ramat Gan 52900 Israel

Ph:  972-3-5317638
FAX: [phone]

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ImageJ mailing list: http://imagej.nih.gov/ij/list.html

[Wayne Rasband-2]

> On Nov 10, 2018, at 4:15 PM, Aryeh Weiss <[hidden email]> wrote:
>
> I want to built a ResultsTable by adding a set of column to the ResultsTable.
>
> my code is:
>
> for i in objectIndicesSet:
>     tempAreaList =  [objectAreas[j] for j in range(len(objectAreas)) if objectIndices[j] == i]
>     print tempAreaList
>     # here is where I wodl like to reset the Counter
>     for k in tempAreaList:
>         rtRearranged.incrementCounter()
>         rtRearranged.addValue("Object "+str(i), k)
>
> where I am adding the list tempAreaList to a column labeled "Object #"
>
> This works, except that I cannot find a way to reset the Counter, so when the second column is written (ie when "Object #" changes, and a new column is automatically created), the counter is still on the last row and the next column starts there. What I really want to do is have the new column start at the first row again,     as I indicate with a comment above.
>
> Is this possible,  or do I have to create all of the area lists, and the write tehm out one row at a time?

Use rt.setValue(column,rowIndex,value) instead of rt.addValue(column,value).

-wayne
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ImageJ mailing list: http://imagej.nih.gov/ij/list.html

[Aryeh Weiss]

On 12/11/2018 22:02, Wayne Rasband wrote:

>> On Nov 10, 2018, at 4:15 PM, Aryeh Weiss <[hidden email]> wrote:
>>
>> I want to built a ResultsTable by adding a set of column to the ResultsTable.
>>
>> my code is:
>>
>> for i in objectIndicesSet:
>>      tempAreaList =  [objectAreas[j] for j in range(len(objectAreas)) if objectIndices[j] == i]
>>      print tempAreaList
>>      # here is where I wodl like to reset the Counter
>>      for k in tempAreaList:
>>          rtRearranged.incrementCounter()
>>          rtRearranged.addValue("Object "+str(i), k)
>>
>> where I am adding the list tempAreaList to a column labeled "Object #"
>>
>> This works, except that I cannot find a way to reset the Counter, so when the second column is written (ie when "Object #" changes, and a new column is automatically created), the counter is still on the last row and the next column starts there. What I really want to do is have the new column start at the first row again,     as I indicate with a comment above.
>>
>> Is this possible,  or do I have to create all of the area lists, and the write tehm out one row at a time?
> Use rt.setValue(column,rowIndex,value) instead of rt.addValue(column,value).
>
> -wayne
> --

Thank you, Wayne. Works as advertised.

I  had not realized that the setValue command will also automatically
add a column if it does not exist, same as the addValue command.

Best regards
--aryeh

--
Aryeh Weiss
Faculty of Engineering
Bar Ilan University
Ramat Gan 52900 Israel

Ph:  972-3-5317638
FAX: [phone]

--
ImageJ mailing list: http://imagej.nih.gov/ij/list.html