Re: polite request - FracLac

Posted by Gabriel Landini on Dec 15, 2010; 2:54pm
URL: http://imagej.273.s1.nabble.com/polite-request-FracLac-tp3686183p3686184.html

On Wednesday 15 December 2010 13:19:15 you wrote:

> extremely time-consuming). Because of such reasons I tried to calculate
> frac. dimension by FracLac. However, I face the problem how to get results
> similar to those obtained by "handy technique". In "handy" technique the
> grid calibres are derived from the longest side of an image analysed that
> is 256 mm. 256 mm is also length of the largest box, all smaller calibres
> are calculated as 256/2n, where n is the exponent and takes values 1, 2,
> 3...8. Then, Fractal dimension is calculated as the slope of ln N(e)
> against ln (1/e), with the fitted line constrained to pass through the
> origin. My problem is, that I do not know how to set the box-counting
> method in FracLac to get similar result. If anybody could help, I really
> appreciate all advices in this issue!!!

Hi Matej,
There is a box counting built in ImageJ and you can specify the boxes:
 Analyze>Tools>Fractal Box count. This is quite fast.

I would suggest to use box sizes that are meaningful to the structure/pattern
that you are analysing, rather than the image size.

Why constraining the fitting line to pass through the origin? That does not
make sense unless you can prove that the scaling is present even at the
smallest scales (quite tricky to do when using digitised images).

Regards

Gabriel