Posted by
b holi on
Mar 26, 2009; 7:19am
URL: http://imagej.273.s1.nabble.com/getDirectory-directory-tp3693180p3693181.html
Glen,
Yes, it is possible but two corrections are needed in your code.
1. The concatenated pathname string to access a folder must include a file
separator character at the end, as below.
2. Your string assignment for 'sumacros' already uses 'getDirectory()' so
it's not needed again in your second line
This will access the folder named 'Startup_macros' with no intervening
Dialog window:
__________
sumacros=getDirectory("macros")+"Startup_macros"+File.separator;
if (File.exists(sumacros)) {
list = getFileList(sumacros);
for (i=0; i<list.length; i++) {
if (endsWith(list[i],'/'))
print(list[i]+' is a folder');
else
print(list[i]+' is a file');
}
print('');
}
else
showMessage('The directory '+sumacros+' was not found.');
______________________
-Bruce
On Fri, Mar 20, 2009 at 5:13 PM, Glen MacDonald <
[hidden email]>wrote:
> Hi,
> Is is possible to select a directory in a macro without bringing up a user
> dialog? getDirectory("macros") will provide the path without dialog.
> But, this brings up the user selection dialog:
>
> sumacros=getDirectory("macros")+"Startup_macros";
> list = getFileList(getDirectory(sumacros));
>
> thanks,
> Glen
>
>
> Glen MacDonald
> Core for Communication Research
> Virginia Merrill Bloedel Hearing Research Center
> Box 357923
> University of Washington
> Seattle, WA 98195-7923 USA
> (206) 616-4156
>
[hidden email]
>
>
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>
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