http://imagej.273.s1.nabble.com/How-to-define-a-3D-array-tp3695869p3695873.html
> Mike,
>
> what you suggest is not the same! Your arrays have a total of 30 elements,
> the one that Sasmitha needs has 1000 elements!
>
> Sasmitha,
>
> You can´t really, there are not even 2D arrays in a macro, you needs to
> create a single array of 1000 elements and use
> explicit indexing, i.e, instead of
>
> a[i][j][k] (i, j, k, = 0..9)
>
> use
>
> a[i*100+j*10+k]
>
> JW
>
> ImageJ Interest Group <
[hidden email]> schrieb am 17.06.2008 10:47:36:
>
>
>> Sasmita:
>>
>> One (huckery) way that I've done this in a macro is to do something like:
>>
>> arrayX = newArray(10);
>> arrayY = newArray(10);
>> arrayZ = newArray(10);
>>
>> Which will give you 3 arrays with 10 empty elements that you can then
>> retrieve using the same index:
>>
>> This snippet will list all your 3 dimensional positions.
>> for (i = 0; i <10; i++){
>> print(arrayX[i], arrayY[i], arrayZ[i]);
>> }
>>
>> So long as you keep your array indices synchronised your 3 arrays will
>> represent 3D positions.
>>
>> Alternatives to 3D arrays suggested on the IJ website are to use
>> setPixel() and getPixel() in a stack that's big enough to hold your
>> data, or make a 1D array and do your own indexing:
>>
http://rsb.info.nih.gov/ij/developer/macro/functions.html#N>>
>> You also don't have to declare your array as type int, the language will
>> do that for you.
>>
>> Mike
>>
>> Sasmita Rath wrote:
>>
>>> Dear ImageJ Group,
>>> Could you please tell me how to define a 3 dimensional array in a
>>>
> macro.
>
>>> I 'm using the syntax :
>>> int name[][][]=new int [10][10][10];
>>>
>>>
>>> but it's not working in ImageJ.
>>>
>>> Thank you.
>>> Sasmita
>>>
>>>
>
>
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