Re: subtraction of images

Posted by Michael Schmid on Jun 04, 2008; 9:43am
URL: http://imagej.273.s1.nabble.com/subtraction-of-images-tp3696059p3696060.html

Hi Oliver,

The documentation of Image Calculator says:

     Subtract     img1 =  img1-img2
     Difference   img1 = |img1-img2|

So "Difference" will be zero for all pixels where two images
are the same. Is this what you are looking for?

http://rsb.info.nih.gov/ij/docs/menus/process.html#calculator

By the way, Process>Math>Subtract subtracts a constant, not an
image.

Michael
________________________________________________________________

On 4 Jun 2008, at 11:22, Oliver Bannach wrote:

> Dear imagej experts
>
> What I like to do is basically a subtraction of images (imageA  
> minus imageB). But each pixel yielding a signal in imageA must be  
> set to zero, if it also appears in imageB, regardless of signal  
> intensities. In other words: Any colocalized pixel must be black in  
> image A. The conventional subtract process (Process->Math-
> >Substract) does not work for me, since the pixel intensities in  
> ImageA are only reduced by values of ImageB pixels. Can I use  
> imageJ standard operations for this purpose or do I need a plugin?  
> Any help is greatly appreciated. Thanky you in advance.
>
> Cheers
> Oliver