Re: subtraction of images

Posted by Oliver Bannach on Jun 04, 2008; 11:06am
URL: http://imagej.273.s1.nabble.com/subtraction-of-images-tp3696059p3696061.html

Hi Michael,

thank you for your suggestion, but that's not exactly what I was looking
for.
It should look like shown in this example (white=0, black=255):

http://www.biophys.uni-duesseldorf.de/~bannach/ImageJ/example.jpg

Any ideas how to do that?

Thanks
Oliver

Michael Schmid schrieb:

> Hi Oliver,
>
> The documentation of Image Calculator says:
>
>     Subtract     img1 =  img1-img2
>     Difference   img1 = |img1-img2|
>
> So "Difference" will be zero for all pixels where two images
> are the same. Is this what you are looking for?
>
> http://rsb.info.nih.gov/ij/docs/menus/process.html#calculator
>
> By the way, Process>Math>Subtract subtracts a constant, not an
> image.
>
> Michael
> ________________________________________________________________
>
> On 4 Jun 2008, at 11:22, Oliver Bannach wrote:
>
>> Dear imagej experts
>>
>> What I like to do is basically a subtraction of images (imageA minus
>> imageB). But each pixel yielding a signal in imageA must be set to
>> zero, if it also appears in imageB, regardless of signal intensities.
>> In other words: Any colocalized pixel must be black in image A. The
>> conventional subtract process (Process->Math->Substract) does not
>> work for me, since the pixel intensities in ImageA are only reduced
>> by values of ImageB pixels. Can I use imageJ standard operations for
>> this purpose or do I need a plugin? Any help is greatly appreciated.
>> Thanky you in advance.
>>
>> Cheers
>> Oliver