Re: Help with Dynamic Range Please

Posted by Bruno on Feb 08, 2008; 9:50am
URL: http://imagej.273.s1.nabble.com/Help-with-Dynamic-Range-Please-tp3697256p3697257.html

Hi,

You can do this with subtract & multiply.
Assum 'low' and 'high' values as range.
Just do Process> Math > subtract 'low'
next Process> Math > muliply ('high' - 'low').
and Process> Math > max 16383

You end up with an image with pixel value ranging form 0-16383.