I neglected to mention that there are many fibers of slightly varying radii
On 8/8/07, Rotella, Anthony M. (GRC)[] <
>
> Paxton,
>
> I must be confused about your problem. If you know that the
> radius value will be the biggest value in the map, then doesn't this
> work :
>
> function findRadius(){
> radius = -1;
> for(c = 0; c < getWidth(); c++)
> for(r = 0; r < getHeight(); r++){
> if (getPixel(c,r) > radius)
> radius = getPixel(c,r); }
> return radius;
> }
>
> Tony
>
>
> >-----Original Message-----
> >From: ImageJ Interest Group [mailto:
[hidden email]] On
> >Behalf Of Paxton Provitera
> >Sent: Wednesday, August 08, 2007 3:46 PM
> >To:
[hidden email]
> >Subject: tube diameter
> >
> >Hi.
> >I have images that I have thresholded and then run through
> >Process>Binary>Distance Map.
> >
> >The images are of tubes in which I would like to extract the
> >radius value (or the largest and center value given by the
> >distance map).
> >
> >The images vary in size but are mostly 640x480.
> >From the following example pixel values I want to extract only
> >the value of
> >6:
> >
> >
> >Sample pixel values from a distance map image:
> >
> >0 0 0 0 0 0 1 2 3 4 5 6 6 5 4 3 2 1 0 0 0 0 0 0 0 0 0 0 1 2 3
> >4 5 6 6 5 4 3 2 1 0 0 0 0 0 0 0 0 0 0 0 0 1 2 3 4 5 6 6 5 4 3
> >2 1 0 0 0 0 0 0 0 0 0 0 0 0 1 2 3 4 5 6 6 5 4 3 2 1 0 0 0 0 0
> >0 0 0 0 0 0 0 1 2 3 4 5 6 6 5 4 3 2 1 0 0 0
> >
> >I've been stuck on some algorithm to extract the relevant information.
> >Thanks for any help on this.
> >
> >-Paxton
> >
>