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Re: How to change value in Results table instead of insert

Posted by Rasband, Wayne (NIH/NIMH) [E] on Apr 10, 2014; 11:02pm
URL: http://imagej.273.s1.nabble.com/How-to-change-value-in-Results-table-instead-of-insert-tp5007271p5007272.html

On Apr 10, 2014, at 6:01 PM, Peter van Loon wrote:

> Hi,
>
> I tried to change an existing value in the Results Table by the macro
> function: setResult("Column", row, value). This works, the value of the
> given row and column is changed the it behaves like an insert. All rows from
> the given row number and all rows below 'move' to the next row. The last row
> disappears.

This bug was fixed in ImageJ 1.48t. Here is the relevant description from the release notes (http://imagej.nih.gov/ij/notes.html):

   Thanks to Ted Toal, fixed a bug in the setResult() macro
   function that caused it to not work as expected when
   changing a string value in the Results table.

You can use the Help>Update ImageJ command to upgrade to the latest version of ImageJ (1.48u).

-wayne

> I checked this by setting the values manually by a simple macro:
>
> /macro " Set Results table [s]" {
> rowIndex = getNumber("rowIndex", 0)
> setResult("Comment", rowIndex,"rowIndex: "+rowIndex+" nResults:"+nResults);
> }/
>
> First I filled the table with 6 values from rowindex 0..6.
> *Results Table:
> 1 rowIndex: 0 nResults:0
> 2 rowIndex: 1 nResults:1
> 3 rowIndex: 2 nResults:2
> 4 rowIndex: 3 nResults:3
> 5 rowIndex: 4 nResults:4
> 6 rowIndex: 5 nResults:5
> 7 rowIndex: 6 nResults:6*
>
> Then I added again rowindex 2.
> *Results Table:
> 1 rowIndex: 0 nResults:0
> 2 rowIndex: 1 nResults:1
> 3 rowIndex: 2 nResults:7
> 4 rowIndex: 2 nResults:2
> 5 rowIndex: 3 nResults:3
> 6 rowIndex: 4 nResults:4
> 7 rowIndex: 5 nResults:5*
>
> The last row disappeared, rowindexes 2..5 moved to the next row, rowindex 2
> was filled with the new string.
>
> Is there a way to change values of Results table and not insert a value?
> I was thinking of filling and updating an array and at last fill the Results
> table rows one by one from this array but I think there must be a better
> way.
>
> Regards,
> Peter
>
> --
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