> In case it matters, the following macro function (that works similarly
> in Java) does it in a handcrafted fashion:
>
> ///////
> requires("1.53f");
> string = preZeros( d2s( PI, 5 ), 3 );
> print( string );
>
> function preZeros( inStr, n ){
> if ( inStr.contains( "." ) ) {
> str = split( inStr, "[.]" );
> inStr = str[0];
> dec = "." + str[1];
> }
> while ( inStr.length() < n ) inStr = "0" + inStr;
> return inStr + dec;
> }
> //////
>
> Have fun
>
> Herbie
>
> ::::::::::::::::::::::::::::::::::::::::::
> Am 21.11.20 um 13:33 schrieb Stein Rørvik:
>> Peter,
>>
>> If what you want to do is to zero pad an integer,
>> you can do this by formatting it as a float specifying zero decimals:
>>
>> s = String.format("%04.0f", 13);
>> print(s);
>>
>> prints 0013
>>
>> str = String.format("%09.5f", PI);
>> print(str);
>>
>> prints 003.14159
>>
>> The last syntax is useful as it allows for more complex number
>> formatting.
>> You can for example pad with spaces instead:
>> str = String.format("% 9.5f", PI);
>>
>> Apparently, String.format does not work as expected with numbers if
>> you omit the .n decimal specification in the format string.
>>
>> The IJ.pad() function is easier to use, but only works with integers.
>>
>> Stein
>>
>> -----Original Message-----
>> Sent: 18. november 2020 16:54
>> Subject: String.format
>>
>> Hi,
>> I would like to execute the macro function:
>>
>> s = String.format("%04d", 13);
>> print(s);
>>
>> but I get the error message
>> "java.util.IllegalFormatConversionException: d != java.lang.Double in
>> line 1:"
>> "s = String . format ( "%04d" , 13 <)> ;"
>>
>> If the number is float and not integer It's working:
>>
>> s = String.format("%04f", 13.0);
>> print(s);
>>
>> Could this be a bug?
>>
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