Passing arrays to functions without declaring an array variable first

[Stein Rørvik]

Assuming a macro function accepting an array as a parameter:

function printArray(a) {
                print("");
                for (i=0; i<a.length; i++)
                               print(i+": "+a[i]);
}

What is the reason this works:

arr = newArray("cat", "dog", "mouse", "rabbit");
printArray(arr);

But not this:

printArray(newArray("cat", "dog", "mouse", "rabbit"));

?

Stein

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[Herbie]

Good day Stein,

in your second example there is no name of the array but there need to be
one because the array is "in a certain sense returned" after the execution
of the function. In your second example there is no variable for the
"returned" array.

HTH

Herbie

::::::::::::::::::::::::::::::::::::::::::

Assuming a macro function accepting an array as a parameter:

function printArray(a) {
                print("");
                for (i=0; i<a.length; i++)
                               print(i+&quot;: &quot;+a[i]);
}

What is the reason this works:

arr = newArray(&quot;cat&quot;, &quot;dog&quot;, &quot;mouse&quot;,
&quot;rabbit&quot;);
printArray(arr);

But not this:

printArray(newArray(&quot;cat&quot;, &quot;dog&quot;, &quot;mouse&quot;,
&quot;rabbit&quot;));

?

Stein

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&lt;/quote>




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[Wayne Rasband-2]

> On Nov 23, 2019, at 1:07 PM, Stein Rørvik <[hidden email]> wrote:
>
> Assuming a macro function accepting an array as a parameter:

The latest ImageJ daily build (1,52s59) fixes a bug in the macro interpreter that prevented built in array functions like newArray(), split() and getProfile() from being used as arguments when calling user-defined functions.

-wayne

> function printArray(a) {
>                print("");
>                for (i=0; i<a.length; i++)
>                               print(i+": "+a[i]);
> }
>
> What is the reason this works:
>
> arr = newArray("cat", "dog", "mouse", "rabbit");
> printArray(arr);
>
> But not this:
>
> printArray(newArray("cat", "dog", "mouse", "rabbit"));
>
> ?
>
> Stein

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