Dear Christophe,
I must say that this behaves as I would expect.
macro "test" {
nameArray = newArray("abcd.tif", "efgh.tif");
print("lenght of nameArray: "+ nameArray.length);
extArray = newArray(nameArray.length);
print("lenght of extArray: "+ extArray.length);
print(extArray[0])
}
Prints:
lenght of nameArray: 2
lenght of extArray: 1
2
As extArrray has only one value, being 2
But you are correct, an older version of Fiji gives,
lenght of nameArray: 2
lenght of extArray: 2
0
Also extArray[1] give as value 0
Best wishes
Kees
Dr Ir K.R. Straatman
Senior Experimental Officer
Advanced Imaging Facility
Centre for Core Biotechnology Services
University of Leicester
www.le.ac.uk/advanced-imaging-facility
-----Original Message-----
From: Christophe Leterrier [mailto:
[hidden email]]
Sent: 19 February 2018 10:50
To:
[hidden email]
Subject: Strange bug using array.length in latest ImageJ
Hi,
Since updating Fiji/ImageJ last week (I guess it's the 1.51u update) my macros are failing when trying to assign a value into an array. I could isolate the problem using this macro:
macro "test" {
nameArray = newArray("abcd.tif", "efgh.tif"); print("lenght of nameArray: "+ nameArray.length); extArray = newArray(nameArray.length); print("lenght of extArray: "+ extArray.length); }
which prints:
lenght of nameArray: 2
lenght of extArray: 1
Why is extArray not the same length as nameArray? This is what is causing the error when I subsequently try to assign a value to extArray[1]. I am positive that newArray(otherArray.length) used to work as I am using it a lot in my macros. What happens here?
Thank you for your help,
Christophe
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