analysis of circular interference

[akash verma]

Hello
Can anybody tell me how to analyze circular interference in Image J.
I have to find out the amplitude of that interference image.
Thanking in advance

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[CARL Philippe (LBP)]

Dear Akash,

Did you already try the Radial Profile plugin
(http://rsbweb.nih.gov/ij/plugins/radial-profile.html) which able you to
extract a radial intensity profile from a picture?

And in the case you need to make a restriction over a given opening angle
there is the (http://rsbweb.nih.gov/ij/plugins/radial-profile-ext.html)
plugin.

I had written the last one quite some years ago, so if you have questions
about it you can contact me.

Best regards,

Philippe

 

-----Message d'origine-----
De : ImageJ Interest Group [mailto:[hidden email]] De la part de Akash
Verma
Envoyé : lundi 17 décembre 2012 07:07
À : [hidden email]
Objet : analysis of circular interference

 

Hello

Can anybody tell me how to analyze circular interference in Image J.

I have to find out the amplitude of that interference image.

Thanking in advance

 

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http://imagej.nih.gov/ij/list.html


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[akash verma]

Thanks Sir
Sir actually i have circular interference pattern from which i have to
reconstruct amplitude image. I am attaching one of that image for which i
have form an amplitude image.

On Mon, Dec 17, 2012 at 1:53 PM, Philippe CARL <[hidden email]>wrote:

> Dear Akash,
>
> Did you already try the Radial Profile plugin
> (http://rsbweb.nih.gov/ij/plugins/radial-profile.html) which able you to
> extract a radial intensity profile from a picture?
>
> And in the case you need to make a restriction over a given opening angle
> there is the (http://rsbweb.nih.gov/ij/plugins/radial-profile-ext.html)
> plugin.
>
> I had written the last one quite some years ago, so if you have questions
> about it you can contact me.
>
> Best regards,
>
> Philippe
>
>
>
> -----Message d'origine-----
> De : ImageJ Interest Group [mailto:[hidden email]] De la part de
> Akash
> Verma
> Envoyé : lundi 17 décembre 2012 07:07
> À : [hidden email]
> Objet : analysis of circular interference
>
>
>
> Hello
>
> Can anybody tell me how to analyze circular interference in Image J.
>
> I have to find out the amplitude of that interference image.
>
> Thanking in advance
>
>
>
> --
>
> ImageJ mailing list:  <http://imagej.nih.gov/ij/list.html>
> http://imagej.nih.gov/ij/list.html
>
>
> --
> ImageJ mailing list: http://imagej.nih.gov/ij/list.html
>

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[akash verma]

Thanks Sir
Sir actually i have circular interference pattern from which i have to
reconstruct amplitude image. I am attaching one of that image for which i
have form an amplitude image.

>
>>

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[Michael Schmid]

Hi Akash,

first draw a circle (ellipse tool, hold shift down) of roughly the size of one of the inner rings. Align it accurately with the pattern by shifting it (it should be exactly concentric).
Then press command-shift (Mac) or CTRL-shift (PC) to extend the circle, keeping the center in its original position, as much as you can without extending beyond the edge of the image.

Then use the Radial Profile plugin
    http://rsb.info.nih.gov/ij/plugins/radial-profile.html
You can use the default settings; it will read the coordinates from the circular selection of the image, so you need not change the numbers in the dialog.

Michael
________________________________________________________________
On Dec 17, 2012, at 12:43, Akash Verma wrote:

> Thanks Sir
> Sir actually i have circular interference pattern from which i have to
> reconstruct amplitude image. I am attaching one of that image for which i
> have form an amplitude image.

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[akash verma]

Hello Sir
I have to find out amplitude images from  close  fringe pattern. I am not
able to that. Please help me.  Close  fringe pattern is given in my
previous mail. I am not able to do that by taking the fourier transform
since Dc peak is at center and first order peak are around it. So am not
able to extract amplitude information.
Thanks in advance
Akash Kumar



On Mon, Dec 17, 2012 at 10:21 PM, Michael Schmid <[hidden email]>wrote:

> Hi Akash,
>
> first draw a circle (ellipse tool, hold shift down) of roughly the size of
> one of the inner rings. Align it accurately with the pattern by shifting it
> (it should be exactly concentric).
> Then press command-shift (Mac) or CTRL-shift (PC) to extend the circle,
> keeping the center in its original position, as much as you can without
> extending beyond the edge of the image.
>
> Then use the Radial Profile plugin
>     http://rsb.info.nih.gov/ij/plugins/radial-profile.html
> You can use the default settings; it will read the coordinates from the
> circular selection of the image, so you need not change the numbers in the
> dialog.
>
> Michael
> ________________________________________________________________
> On Dec 17, 2012, at 12:43, Akash Verma wrote:
>
> > Thanks Sir
> > Sir actually i have circular interference pattern from which i have to
> > reconstruct amplitude image. I am attaching one of that image for which i
> > have form an amplitude image.
>
> --
> ImageJ mailing list: http://imagej.nih.gov/ij/list.html
>

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[Michael Schmid]

Hi Akash,

the Fourier transform won't help you since the fringes do not have a constant spacing (there are many spatial frequencies). You have to look at the radial profile, see the previous mails.

Michael
________________________________________________________________
On Dec 19, 2012, at 18:58, Akash Verma wrote:

> Hello Sir
> I have to find out amplitude images from  close  fringe pattern. I am not
> able to that. Please help me.  Close  fringe pattern is given in my
> previous mail. I am not able to do that by taking the fourier transform
> since Dc peak is at center and first order peak are around it. So am not
> able to extract amplitude information.
> Thanks in advance
> Akash Kumar
>
>
>
> On Mon, Dec 17, 2012 at 10:21 PM, Michael Schmid <[hidden email]>wrote:
>
>> Hi Akash,
>>
>> first draw a circle (ellipse tool, hold shift down) of roughly the size of
>> one of the inner rings. Align it accurately with the pattern by shifting it
>> (it should be exactly concentric).
>> Then press command-shift (Mac) or CTRL-shift (PC) to extend the circle,
>> keeping the center in its original position, as much as you can without
>> extending beyond the edge of the image.
>>
>> Then use the Radial Profile plugin
>>    http://rsb.info.nih.gov/ij/plugins/radial-profile.html
>> You can use the default settings; it will read the coordinates from the
>> circular selection of the image, so you need not change the numbers in the
>> dialog.
>>
>> Michael
>> ________________________________________________________________
>> On Dec 17, 2012, at 12:43, Akash Verma wrote:
>>
>>> Thanks Sir
>>> Sir actually i have circular interference pattern from which i have to
>>> reconstruct amplitude image. I am attaching one of that image for which i
>>> have form an amplitude image.

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[Daddymoen]

Just a thouht,

If your interference pattern is anything like  the pattern of light and dark bands in the double slit experiment their should be an analogous circular pattern of dark and light bands.  These should be detectable as variations in pixel intensity amplitude.  A plugin or macro that creates a pseudo colored "plot" of pixel intensity variation..  Mathematical analysis of factors like mean intensity, peak intensity, standard deviation, peak frequency etc. should be possible.

You probably knew that.  Schlieren and digital shadow graph photography might be useful concepts.

Daddymoen

akash verma wrote

Hello
Can anybody tell me how to analyze circular interference in Image J.
I have to find out the amplitude of that interference image.
Thanking in advance

--
ImageJ mailing list: http://imagej.nih.gov/ij/list.html

[akash verma]

Hello
Sir
I am unable to find out the amplitude image of a circular interference
image.
Despite my lot effort i am getting i am unable to do that.
Please help me its necessary for me.
Thanks in advance

On Sat, Dec 22, 2012 at 11:21 AM, Daddymoen <[hidden email]> wrote:

> Schlieren and digital shadow graph photography
> might be useful concepts.
>

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[Herbie-2]

Dear,

as far as I understand your desire, you wish to retrieve the phase
information from an intensity diffraction pattern, in order to
reconstruct the amplitude diffraction pattern.

This problem is ill-posed and in general can't be solved exactly and
uniquely. However there are techniques for obtaining approximate solutions.
I'm not aware of any existing IJ-plugins or IJ-macros for doing this,
although they may exist.

A classical approach is the Gerchberg-algorithm.

HTH

Herbie

_____________________________________
On 24.12.12 14:47, Akash Verma wrote:

> Hello
> Sir
> I am unable to find out the amplitude image of a circular interference
> image.
> Despite my lot effort i am getting i am unable to do that.
> Please help me its necessary for me.
> Thanks in advance
>
> On Sat, Dec 22, 2012 at 11:21 AM, Daddymoen<[hidden email]>  wrote:
>
>> Schlieren and digital shadow graph photography
>> might be useful concepts.
>>
>
> --
> ImageJ mailing list: http://imagej.nih.gov/ij/list.html
>

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[akash verma]

Sorry for confusion

> I have four  90 degree phase shifted interferogram  of a circular lens.
> whose frequency spacing is not constant and i have to find out phase and
> amplitude. I am attaching one of those interferograms
>
> On Wed, Dec 26, 2012 at 5:55 PM, Herbie <[hidden email]> wrote:
>
>> Dear,
>>
>> it is no fun trying to help someone who doesn't explain what he was doing
>> and what he desires to come up with. You're posting since many days to the
>> list and didn't tell what you are/were really doing. How can one help
>> someone who is not able or willing to tell what's really going on.
>>
>> Evidently, a diffraction pattern in general is complex-valued, i.e. you
>> need two "images" to describe it, either modulus and phase, or real and
>> imaginary part. You say you've got the phase image and of course you've got
>> the modulus image. So you've got all you need.
>>
>> If you've got all you need what is missing and what comes out wrong?
>>
>> What are you going to do with the complex-valued diffraction pattern?
>>
>> I'm totally unclear what you are heading for and I'm not willing to help
>> someone who is unable to explain the most basic facts.
>>
>> Go to your adviser and ask for help if you are unable to solve the
>> problem yourself.
>>
>> Good luck
>>
>> Herbie
>>
>>
>>
>> On 25.12.12 17:38, Akash Verma wrote:
>>
>>> sir, i had got the phase through 4-step phase shifting
>>> algorthim(phase=arctan(I4-I2/**I1-I3) but when i am taking the amplitude
>>> =sqrt((i4-I2)^2+(I1-I3)^2) ..........its not giving the desired result.
>>>
>>> On Tue, Dec 25, 2012 at 7:18 PM, Herbie <[hidden email]
>>> <mailto:[hidden email]>> wrote:
>>>
>>>     Dear,
>>>
>>>     evidently the modulus of the amplitude is just the square root of
>>>     the intensity. Now, if you know the phase, you've got all it takes
>>>     for the reconstruction.
>>>
>>>     BTW, I don't understand how you found out about the phase. What do
>>>     you mean by "phase shifting algorithm"?
>>>
>>>     Best
>>>
>>>     Herbie
>>>
>>>
>>>     On 25.12.12 13:36, Akash Verma wrote:
>>>
>>>         hello Sir
>>>         I had found the phase through phase shifting algorithm , but
>>>         when took
>>>         the amplitude i am not able to extract that.
>>>         Its given interference pattern .
>>>
>>>         On Tue, Dec 25, 2012 at 5:05 PM, Herbie <[hidden email]
>>>         <mailto:[hidden email]>
>>>         <mailto:[hidden email] <mailto:[hidden email]>>> wrote:
>>>
>>>              Gerchberg-algorithm
>>>
>>>
>>>
>>>
>>>
>>
>

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[Cammer, Michael]

I've been watching this request get posted to the listserv repeatedly.  
Since I have a little time this week, I looked at the picture you posted and wonder whether you are looking for a simple analysis such as http://www.flickr.com/photos/mcammer/8311692552/
Is this at all helpful?
Regards,
Michael
________________________________________________________
Michael Cammer, Assistant Research Scientist
Skirball Institute of Biomolecular Medicine
Lab: [phone]  Cell: [phone]

-----Original Message-----
From: ImageJ Interest Group [mailto:[hidden email]] On Behalf Of Akash Verma
Sent: Wednesday, December 26, 2012 1:02 PM
To: [hidden email]
Subject: Re: analysis of circular interference

Sorry for confusion
> I have four  90 degree phase shifted interferogram  of a circular lens.
> whose frequency spacing is not constant and i have to find out phase
> and amplitude. I am attaching one of those interferograms
>

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[akash verma]

Thanks Sir

On Wed, Dec 26, 2012 at 11:49 PM, Cammer, Michael <
[hidden email]> wrote:

> I've been watching this request get posted to the listserv repeatedly.
> Since I have a little time this week, I looked at the picture you posted
> and wonder whether you are looking for a simple analysis such as
> http://www.flickr.com/photos/mcammer/8311692552/
> Is this at all helpful?
> Regards,
> Michael
> ________________________________________________________
> Michael Cammer, Assistant Research Scientist
> Skirball Institute of Biomolecular Medicine
> Lab: [phone]  Cell: [phone]
>
> -----Original Message-----
> From: ImageJ Interest Group [mailto:[hidden email]] On Behalf Of
> Akash Verma
> Sent: Wednesday, December 26, 2012 1:02 PM
> To: [hidden email]
> Subject: Re: analysis of circular interference
>
> Sorry for confusion
> > I have four  90 degree phase shifted interferogram  of a circular lens.
> > whose frequency spacing is not constant and i have to find out phase
> > and amplitude. I am attaching one of those interferograms
> >
>
> --
> ImageJ mailing list: http://imagej.nih.gov/ij/list.html
>

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[akash verma]

Sir
This is what excatly what i want. Closed fringes to open fringes.
Can you tell me the procedure.Since i am new to image j.
Thanks in advance

On Wed, Dec 26, 2012 at 11:49 PM, Cammer, Michael <
[hidden email]> wrote:

> I've been watching this request get posted to the listserv repeatedly.
> Since I have a little time this week, I looked at the picture you posted
> and wonder whether you are looking for a simple analysis such as
> http://www.flickr.com/photos/mcammer/8311692552/
> Is this at all helpful?
> Regards,
> Michael
> ________________________________________________________
> Michael Cammer, Assistant Research Scientist
> Skirball Institute of Biomolecular Medicine
> Lab: [phone]  Cell: [phone]
>
> -----Original Message-----
> From: ImageJ Interest Group [mailto:[hidden email]] On Behalf Of
> Akash Verma
> Sent: Wednesday, December 26, 2012 1:02 PM
> To: [hidden email]
> Subject: Re: analysis of circular interference
>
> Sorry for confusion
> > I have four  90 degree phase shifted interferogram  of a circular lens.
> > whose frequency spacing is not constant and i have to find out phase
> > and amplitude. I am attaching one of those interferograms
> >
>
> --
> ImageJ mailing list: http://imagej.nih.gov/ij/list.html
>

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