threshold' in the Measurements options. Then you get the thresholded
> Dear Michael, thanks a lot. I've reach my objective.
> Finally, do you think I could have the crude values of the areas (in the
> ROI and colored) instead the percentage?
>
> Thanks a lot for everything and I hope to stop my questions.
>
> Alberto Contri
>
> 2016-04-04 9:46 GMT+02:00 Michael Schmid-3 [via ImageJ] <
>
[hidden email]>:
>
>> Hi Alberto,
>>
>> if you have selected 'Area%' in 'Set Measurements', the %Area column
>> gives you the area fraction of the thresholded area (if there is a
>> threshold) or the area with non-zero pixels (if there is no threshold).
>> If you have a binary image with an inverting LUT (as in your case), the
>> black area is non-zero (255), the background is zero.
>>
>> If there is an area selection (=region of interest), the area fraction
>> is for the region inside the selection, ignoring everything else. You
>> can easily try this by selecting a region that contains only black or
>> only white pixels; you will get 100 or 0%, respectively.
>>
>> Michael
>> ________________________________________________________________
>>
>> On 2016-04-04 09:09, albertocontri wrote:
>>
>>> Dear Michael,
>>> thank you for all your explanations.
>>> I'm near the solution of my troubles. I send you the point where I am:
>> the
>>> colored parts are black, the gray one are white.
>>> Now, within the yellow line, I need to have the proportion between the
>>> black area and the area delimited within the yellow line. I tried with
>> the
>>> measure function, and the result table gave me the total area enclosed
>> in
>>> the yellow line and a percent, but I have not understood to what the
>>> percent referred. Maybe it is more simple if the result table give me
>> bith
>>> the areas. I need to limit the evaluation to the region enclosed in the
>>> yellow line, because it is the structure of my interest.
>>>
>>> Thanks a lot
>>>
>>> Alberto
>>>
>>>
>>> 2016-04-03 19:46 GMT+02:00 Michael Schmid-3 [via ImageJ] <
>>> [hidden email] <
http:///user/SendEmail.jtp?type=node&node=5016054&i=0>>:
>>
>>>
>>>> Hi Alberto,
>>>>
>>>> if you just need to distinguish between gray and colored areas, you can
>>>> simply transform the image to an HSB stack (hue/saturation/brightness)
>> and
>>>> threshold the S (saturation) channel. The saturation value is zero for
>>>> gray pixels.
>>>> The small number in the Threshold panel will tell you the fraction of
>> the
>>>> red area in percent while moving the Threshold sliders.
>>>> For a list output (Results Table), use 'Measure' with 'Area Fraction'
>>>> enabled in 'Analyze>Set Measurements'.
>>>>
>>>> Michael
>>>> __________________________________________________________
>>>>
>>>> On Sun, April 3, 2016 14:24, albertocontri wrote:
>>>>
>>>>> Dear dr. Straatman,
>>>>>
>>>>> I'm sorry because I acknowledged you only now for your response.
>>>>> I shelved the project until now, but now it is the time for me to
>>>> complete
>>>>> the work.
>>>>> You suggested me a way to quantify the blue and red areas in my image.
>>>> It
>>>>> is important to say that I don't need to separate the measurement of
>> the
>>>>> blue and red areas, but them could be merged.
>>>>> I try to explain better what the ImageJ should give me. I need to
>>>> quantify
>>>>> the proportion of the blue+red areas compared with the area enclosed
>> in
>>>>> the
>>>>> ROI.
>>>>> I send you another image where I created around the region of interest
>>>>> (ROI) a perimeter with the freehand selections function. Now, I need
>> to
>>>>> calculate the proportion(ratio) between the blue + red areas and the
>>>> area
>>>>> enclosed in the yellow line. I could also calculate the ratio in a
>>>> second
>>>>> time, but I need to have both the areas (total inside the yellow line
>>>> and
>>>>> blue+red areas).
>>>>> I'm able to measure the area inside the yellow line but I'm not able
>> to
>>>>> keep on.
>>>>>
>>>>> I hope you could suggest me how I can complete the analysis.
>>>>>
>>>>>
>>>>> Kind regards and thanks a lot for your time.
>>>>>
>>>>> Alberto Contri
>>>>>
>>>>> 2014-05-06 11:30 GMT+02:00 Straatman, Kees (Dr.) [via ImageJ] <
>>>>> [hidden email] <
http:///user/SendEmail.jtp?type=node&node=5016050&i=0>>:
>>
>>>>
>>>>>
>>>>>> Dear Alberto,
>>>>>>
>>>>>> Try something like color > split channels. Select the individual red
>>>> and
>>>>>> blue channels and run on each a threshold (Image > Adjust >
>> threshold)
>>>>>> with
>>>>>> settings that select the areas you are interested in. Under Analyse >
>>>>>> Set
>>>>>> Measurements select Area and Area fraction and run Analyse > Analyse
>>>>>> Particles for both your red and blue image. Hope this gives the
>> result
>>>>>> you
>>>>>> are after.
>>>>>>
>>>>>> Best wishes
>>>>>>
>>>>>> Kees
>>>>>>
>>>>>> -----Original Message-----
>>>>>> From: ImageJ Interest Group [mailto:[hidden email]
>>>>>> <
http:///user/SendEmail.jtp?type=node&node=5007592&i=0>] On Behalf
>> Of
>>>>>> albertocontri
>>>>>> Sent: 05 May 2014 23:19
>>>>>> To: [hidden email]
>>>>>> <
http:///user/SendEmail.jtp?type=node&node=5007592&i=1>
>>>>>> Subject: color doppler ultrasound quantification
>>>>>>
>>>>>> Hallo everyone,
>>>>>> I'm new of the forum and of ImageJ. Now, I ask a question that have
>>>>>> probably an obvious answer.
>>>>>>
>>>>>> I need to quantify the amount of red and blue pixels in an image, and
>>>>>> the
>>>>>> proportion of the red and blue areas compared to the whole gray
>> image.
>>>>>> The
>>>>>> image that I need to analyze is a color doppler image, in which the
>>>>>> colours
>>>>>> represented the blood vessels. I need to quantify the proportion of
>> the
>>>>>> boold vessels in the organ that I examine. If need, I could attach an
>>>>>> example.
>>>>>>
>>>>>> I hope one of you could help a wretched researcher...
>>>>>>
>>>>>> Thanks in advance
>>>>>>
>>>>>> Alberto
>>>>>>
>>>>>>
>>>>>>
>>>>>> --
>>>>>> View this message in context:
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